Question

how do i solve by factoring 2a^2+3=79? i dont know what steps i need to take or how to show my work on this problem.

Answer 1

\[2a^2+3=79\]
subtract 79 from both sides:
\[2a^2-76=0\]
factor
\[2(a^2-38)=0\]
divide by 2
\[a^2-38=0\]
add 38 to both sides
\[a^2=38\]
square root
\[a=\pm\sqrt{38}\]
So:
\[\large a=\sqrt{38} ;-\sqrt{38}\]