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Mathematics 10 Online
OpenStudy (anonymous):

f(x)= 1/2(x-1)^3 find f'(0) a. -6 b. -3 c. -3/2 d. -1/2 e. 3/2

OpenStudy (anonymous):

is this \[f(x)=\frac{1}{2}(x-1)^3\]?

OpenStudy (anonymous):

or is it \[f(x)=\frac{1}{2(x-1)^3}\]

OpenStudy (anonymous):

its the first one

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