Question

given that x-y=8
and that xy<240
find the maximum value of (x+y) given that x-y=8
and that xy<240
find the maximum value of (x+y) @Mathematics

Answer 1

x-y=8
x=8+y

x*y<240

(y+8)*y<240

y^2+8y<240

y^2+8y-240<0

(y+20)(y-12)<0

y<12,-20

max(y)=12

max(x)=12+8=20

max(x+y)=12+20=32

Answer 2

well, technically, x+y<32 if thats not <=, but ya