Question

Sooo, the answer today was \(\cfrac{7}{6}-ln(\cfrac{3}{2})\); and I had written \(\cfrac{7}{6}+ln(\cfrac{2}{3})\), and could figure out why mine differed .... :)

Answer 1

it just so happens that:\[ln(\frac{2}{3})=-ln(\frac32)\]:o♫♫