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Calculus1
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Help with my exercise please! @Mathematics
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exercise! help
ok, I need to resolve this derivative exercise using the Law of Definition of Derivative
\[\sqrt{9x ^{2}+16}\]
any help please?
write it as\[y=\sqrt {9x ^{2} + 16}\]then let\[z=9x ^{2}+16\]\[dz/dx=18x\]so\[y=\sqrt {z}=z ^{1/2}\]\[dy/dz=(1/2)z ^ {-1/2}=1/2\sqrt {z}=1/2\sqrt {9x ^{2}+16}\]\[dy/dx=dy/dz * dz/dx=(1/2\sqrt {9x ^{2}+16}) * 18x=9x/\sqrt {9x ^{2}+16}\]
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sorry, mis-read your question. i answered this using the law of derivatives in your other post.
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