Question

can someone solve log(x-2) 27 = 3? It's base is the (x-2)

Answer 1

\[\log_{x-2} 27=3\]

Answer 2

\[(x-2)^{3}=27\]
\[x^{3}-6x^{2}+12x-8=3\]
\[x^{3}-6x^{2}+12x-11=0\]
And then factor it or something, idk.

Answer 3

er, I meant
\[x^3-6x^2+12x-8=27\]
\[x^3-6x^2+12x-35=0\]