Question

Find the intercepts y= -4x^2+4x-1

Answer 1

The x-intercept is when y=0. So set it like that.
\[-4x^2+4x-1=0\]
Find out what x is, then you get the point (x,0).


the y-intercept is when x=0.
\[y=-4(0)^2+4(0)-1\]
Find out what y is, then you have (0,y).