Question

Solve the equation for the exact value of x. 2lnx=ln(6x+24)- ln3

Answer 1

2lnx=ln(6x+24)- ln3 using the logarithm laws
lnx^2=ln[(6x+24)/3] taking exponents on both sides

e^lnx^2=e^ln[(6x+24)/3]

x^2=[(6x+24)/3]

x^2=2x+8

x^2-2x-8=0 factoring
(x-4)(x+2)=0
x=4,-2 ans

Answer 2

any question josh

Answer 3

I get it. thanks!