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Mathematics 22 Online
OpenStudy (anonymous):

I found the reduced row echelon form of the matrix A which told me that the Nul basis for A was [{-17,-11,1,8}]. Why is this a basis? I found the reduced row echelon form of the matrix A which told me that the Nul basis for A was [{-17,-11,1,8}]. Why is this a basis? @Mathematics

OpenStudy (anonymous):

can you post the matrix you worked with?

OpenStudy (anonymous):

\[A=\left[\begin{matrix}1 & -2 & 3 & 1 \\ 1 & 0 & 1 & -2\\1 & 1 & 4 & -3\end{matrix}\right]\]. Basis for Col A is just colums 1 2 and 3 of a (pivot colums).

OpenStudy (anonymous):

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OpenStudy (anonymous):

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