Question

h(x)+= -(x+2)(x+6) determine the vertex, x and y int and sketch a graph.

Help please?

Answer 1

at what points odes the function = 0?

Answer 2

when x= ?? and ??

Answer 3

x equals 4 i believe

Answer 4

what values of x whould make h(x) 0?

Answer 5

-2 and -6?

Answer 6

correct

Answer 7

and because of the form of this equation, we know its a parabola

Answer 8

so we know its a parabola that crosses the x axis at -2 and -6

Answer 9

the negitive sign indicates that its upside down

Answer 10

and to find the y int set x=0

Answer 11

you sketch the graph on here using the edit function.. ill check it

Answer 12

wait so which number is the vertex? -2,-6?

Answer 13

h(x)+= -(x+2)(x+6)
h(x)+= -(x^2+8x+12)
h(x)=- -x^2-8x-12 the roots are -2,-6
vertex v=-b/2a=8/(2)(-1)=-4,plug thuis to get h(-4)=4
herefore vertex V(x,y)=V(-4,4)