Question

Logarithm bases are in () Solve: Log(x)log(2x)2=log(4x)2

Answer 1

2logx(logx + logx )=8logx
log2x=4

e^log2x = e^2
2x=e^2
x= (e^2)/2

Answer 2

o^log(4x)2=0, therefore the other are zeroes too?