Question

The perimeter of a triangle is 51 centimeters. Side b is 3 centimeters longer than side a. Side c is 8 centimeters shorter than twice the length of side a. Find the length of each side.

a)
b)
c)

Answer 1

please help ):

Answer 2

a+b+c=51

b=a+3
c=2a-8

sub b and c into the first equation:

a+(a+3)+(2a-8)=51
4a-5=51
4a=56
a=14

Sub a=14 back to get b and c

b=14+3=17
c=2(14)-8=28-8=20

Therefore, a=14, b=17, and c=20