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Divide and check. 49x^7-56x^5+42x^3/7x^3
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49x^7-56x^5+6
factor the top and cacel the bottom
doing that should leave you with 7x^4-8x^2+6
7x^\[7x^{3}(7x^4-8x^2+6) \over7x^3\]
7x^3 cancel
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leaving you with 7x^4-8x^2+6
\[\frac{49x^7-56x^5+42x^3}{7x^3}\] \[=\frac{49x^7}{7x^3}-\frac{56x^5}{7x^3}+\frac{42x^3}{7x^2}\] \[=7x^4-8x^2+6\]
i am not sure how you guys can type math expressions
the equation editor in the bottom
\[\huge skill\]
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lol
well THX all
I dont use the eqn editor, I just type 'em out \[\large \frac{\rho}{\Delta}\int F'(x)dx\] and such
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