Question

how do i do the derivative of 7 square roots of 9Z^3?

Answer 1

\[\large 7\sqrt{9z^{3}}\]

Answer 2

??

Answer 3

yes

Answer 4

you can rewrite as (9z^3)^(1/7)

so we have

(1/7)*[(9z^3)^(1/7 -1)]*(9*3z^(3-1))
(1/7)*[(9z^3)^(-6/7)]*(27z^(2))
(1/7)*[ (9^(-6/7) z^(-18/7)]*(27z^(2))
(1/7)*[ (27*9^(-6/7) z^(-18/7 +2)]
(1/7)*[(27*9^(-6/7) z^(-4/7)]

Answer 5

what rule did you use?

Answer 6

i dont know how to say in English. =/