Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

hint: logistic function
Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

hint: logistic function
@Mathematics

Question

Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

hint:  logistic function
 Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

hint:  logistic function
 @Mathematics

anonymous · Answer

dP/dt=KP
P(0)=6.9x10^6
integral1/PdP=integral kdt
k=.0019

anonymous · Answer

ln(P)=kt+c
P=ce^kt

anonymous · Answer

you need to solve for c by setting t=o