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What is the equation of the line passing through (1, 7) and parallel to the line y = –x + 5 in standard form?
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y=-x+8
parallel lines have the same slope
these are the options: x + y = 8 x – y = 8 x + y = –8 x – y = –8
a
being parallel to y=-x+5 your required equation is y=-x+k(say) as parallel lines have the same slope since the line passes through (1,7) substitute in the above equation 7=-1+k which gives you k=8 therfore the requied equation is y=-x+8
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so its a
Solve the following for x and them move -y from the RHS to the LHS.\[\frac{y-7}{x-1}=-1\] \[x+y=8 \]
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