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Perform the division. 8a2 + 2a − 3 2a − 1
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There's supposed to be a line between the two equations
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Factorise the numerator to (4a+3)(2a-1). The (2a-1) then cancels, leaving 4a+3, which is the equation of a straight line.
how did you figure out (4a+3)(2a-1)
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I guessed that one of the factors of the quadratic was (2a-1) then figured out what you have to multiply by (2a-1) to get 8a^2+2a-3.
It doesn't always work like that, but you should think what the objective of the queestion actually is; it's almost like working backwards to get the answer.
(4a+3)
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