Question

Find the relative extrema of the function f(x)=x^3-2x^2-4x+4 defined on [0,3]
Find the relative extrema of the function f(x)=x^3-2x^2-4x+4 defined on [0,3]
@Mathematics

Answer 1

Find the derivative first.

Answer 2

dy/dx = 3x^2 - 4x - 4

Answer 3

then 3x^2 - 4x - 4 = 0 to find the TP

Is relative extrema the min and max ?

Answer 4

Find the second derivative and compare it to zero. If the second derivative is greater than zero, then it's a minimum. If it's less than zero than it's a maximum.