Question

find the derivative of x^x

Answer 1

x^x(logx+1)

Answer 2

\[y=x^x\iff \ln y=\ln x^x=x\ln x\iff \frac{1}{y}y'=\ln( x)+ 1\]\[y'=y\left(\ln (x)+1\right)\iff y'=x^x\left(\ln (x)+1\right)\]

Answer 3

(@joe: nice, but I know you know that one of those "if and only if" isn't quite right ;-) )

Answer 4

medals needed :P

Answer 5

xx^x-1

Answer 6

ack >.< i tend to get carried away with them lol. noted.