Question

write a program using nested loop to produce the following output:

& & & & & & &
& & & & &
& & &
& write a program using nested loop to produce the following output:

& & & & & & &
& & & & &
& & &
& @Computer Science

Answer 1

public class Printand {
public static void main (String args[]){
System.out.println("&&&&&&&");
System.out.println(" &&&&& ");
System.out.println(" &&& ");
System.out.println(" & ");

Answer 2

umm .... nested loop?

Answer 3

for(int i =4 ; i>=0 ; i--)
{
if(i==4)
System.out.println("&&&&&&&");
else if(i==3)
System.out.println(" &&&&& ");
else if(i==2)
System.out.println(" &&& ");
else if(i==1){
System.out.println(" & ");

Answer 4

that's not nested loop, you should add one within other.
here is your C++ code:

#include <iostream>
using namespace std;

int main(void){
int row=7,col;

for(col=4;col>=1;col--){
for(int null=4;null>col;null--)
cout<<" ";
for(row=row-2*(4-col);row>=1;row--){
cout<<"A";
}
row=7;
cout<<"\n";
}
return(0);
}

Answer 5

If you want to find out the logic, this one is better for you:


#include <iostream>
using namespace std;

int main(void){
int row,col,temp=7,space,a=0;
for(col=4;col>=1;col--){
for(space=0;space<a;space++){
cout<<" ";
}
for(row=temp;row>=1;row--){
cout<<"&";
}

a=a+1;
temp=temp-2;
cout<<"\n";
}

return(0);
}

Answer 6

thanks a lot....:)