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Mathematics
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c=650n+600 repair c=450n+1800 replacement find the number of years for which the total cost of repair would equal the total cost of replacement.
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Set c = c and solve for n
how? can you show me?
c = 650 + 600 c = 450n + 1800 c = c 650n + 600 = 450n + 1800 200n = 1200 n = 1200/200 n = 6
6 years
This is about the easiest version of a systems of equations there is.
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okay i got it it's just that i got a lil confused i mean it's a word problem
This is one of the easiest word problems
associated with systems of equations
I'm scared for you
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