Question

is this double chain rule? e^(xsin2x)

Answer 1

yes

Answer 2

double chain rule with a product rule

Answer 3

which rule do i use? a^x'=a^xlna or e^u=e^udu/dx

Answer 4

e^u=e^udu/dx

Answer 5

[ e^u ] du
u = xsin2x

Answer 6

i get for du/dx x*cos2x*2+sin2x

Answer 7

is that right?

Answer 8

yup

Answer 9

cool beans