In a judo foot-sweep move, you sweep your opponent's left foot out from under him while pulling on his gi (uniform) toward that side. As a result, your opponent rotates around his right foot and onto the mat. Figure shows a simplified diagram of your opponent as you face him, with his left foot swept out. The rotational axis is through point O. The gravitational force on him effectively acts at his center of mass, which is a horizontal distance d = 26 cm from point O. His mass is 67 kg, and his rotational inertia about point O is 65 kg·m2. What is the magnitude of his initial angula

Question

In a judo foot-sweep move, you sweep your opponent's left foot out from under him while pulling on his gi (uniform) toward that side. As a result, your opponent rotates around his right foot and onto the mat. Figure shows a simplified diagram of your opponent as you face him, with his left foot swept out. The rotational axis is through point O. The gravitational force   on him effectively acts at his center of mass, which is a horizontal distance d = 26 cm from point O. His mass is 67 kg, and his rotational inertia about point O is 65 kg·m2. What is the magnitude of his initial angula

anonymous · Answer

http://www.cramster.com/answers-nov-08/physics/fun-question-judo-judo-foot-sweep-move-sweep-youropponents-lef_387130.aspx?rec=0

anonymous · Answer

thats a link to the problem