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In △DEF, what is the length of DF? Image posted. 15 radical 3 30 radical 3 45 radical 2 90
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use \[\sin(60)=\frac{45}{DF}\] and also \[\sin(60)=\frac{\sqrt{3}}{2}\]
Ok thank you! 45 radical 2!
no that is not what i get
\[\frac{\sqrt{3}}{2}=\frac{45}{DF}\] \[\sqrt{3}DF=90\] \[DF=\frac{90}{\sqrt{3}}=\frac{90\sqrt{3}}{3}=30\sqrt{3}\]
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