Question

2+square rt 5: given one solution of a quadratic with rational coefficients, find the other solution. Write a quadratic that has those solutions. 2+square rt 5: given one solution of a quadratic with rational coefficients, find the other solution. Write a quadratic that has those solutions. @Mathematics

Answer 1

\[x=\left( -b \pm \sqrt {b^2 - 4ac} \right)/2a\]

therefore we have \[x=2 \pm \sqrt{5}\]

So your other solution is 2-sqrt(5)

One possible quadratic is \[(1/2)x^2 -2x-1/2=0\]