Question

How do I simplify (x^2 - 6x + 8/2x^2 - 7x +6) - (x^2 - x - 12/ 2x^2 - 5x - 12)?

Answer 1

x^2 - 6x + 8 x^2 - x - 12
----------- - -----------
2x^2 - 7x +6 2x^2- 5x - 12

= (x-4)(x-2) (x-4)(x+3)
--------- - ----------
(2x-3)(x-2) (2x+3)(x-4)

Answer 2

go ahead u r right !!!!!

Answer 3

= (x-4)(2x+3) (x+3)(2x-3)
---------- - ------------
(2x-3)(2x+3) (2x+3)(2x-3)

= (x-4)(2x+3) - (x+3)(2x-3)
-----------------------
(2x-3)(2x+3)

= 2x^2 + 5x - 12 - 2x^2 - 3x +9
----------------------------
(2x-3)(2x+3)

= -8x - 3
-------
(2x-3)(2x+3)

Answer 4

is the answer -8 - 3 the right answer? :(
---------
(2x-3)(2x+3)

Answer 5

no recheck it

Answer 6

what's wrong?

Answer 7

\[\frac{2x^2 -5x -12 - 2x^2 - 3x + 9}{4x^2 - 9} = \frac{-(2x+3)}{(2x-3)(2x+3)} = \frac{-1}{2x-3}\]

Answer 8

-5x was wrong

Answer 9

I've asked two people here and both of you gave me two different answers D:

Answer 10

hahahaha which one is correct??????????

Answer 11

no reply milliex tell me is it correct or not ?

Answer 12

I don't know D:

Answer 13

because one had -7/(2x-3)(2x+3), you have -1/2x-3 and i have -8x-3/(2x-3)(2x+3)

Answer 14

upto my knowledge i m right