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Mathematics 7 Online
OpenStudy (anonymous):

Solve this numerical syllogism for me: Eight of ten A's are B's; four of ten A's are C's. What is the minimum number of B's that are also C's?

OpenStudy (osanseviero):

2 B´s are C´s

OpenStudy (anonymous):

2 Bs would be the minimum number of Bs that can be Cs.

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