y=6x^2+12x+10 1. Change from polynomial form to vertex form 2.does it face up or down 3.vertex 4. y interecept 5. line of symmetery 6. narrow, wide, or parent? 7. is it a min or max help please? i have to give a presentation tomorrow :(
Hey for this question Do you know how to complete the square?
that where im stuck i have the way it faces, min and line of symmetry but I cant seem to complete the square properly
Give me a second this i get this weird answer let me try again
So do you want me to tell you how to complete it first?
sure that would be great :)
y=6x^2+12x+10 0=6x^2+12x+10 Divde the 6 to all of the numbers x^2+2x +10/6= 0 Simplify x^2 +2x+ 5/3 =0 Move the 5/3 to other side by subtracting it. x^2 +2x + (Box)= 5/3 +(box) x^2 +2x + (1) = 5/3 +(1) (x+1)^2 = 8/3 5/3+1 =5/3 +3/3 Square root both sides x+1= square root of 8/3 subtract 1 which is x= 1+ or - square root of 8/3
Sorry its really long haha
that confused me one sec let me think about it haha
Haha Alright but i have to go soon :p
Hope i did it right.
i did it like this 6x^2+12x+10 2(3x^2+6x )+5 2(3x^2+6x+1)+5-2 and thats where i got losst
Oh i see on completing square you cannot factor it like that.
You have to completely divide it :( http://www.purplemath.com/modules/sqrquad.htm Check it out the first question with 4x
oh dang thats how my teacher t aught me :(
So you got the rest down?
yeah once i get it i can finsh soslving because ill know h and k thank you :)
haha no problem i hope you do well and just in case please check it over :( i dont want you to get bad grade because of my mistake
oh dont worry about it haha youve helped me i would have been completely lost lol
Haha Good luck :p good night :3
thanks :) good night
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