Question

Find the equation of the line that is perpendicular to 2x + 5y = 8 and passes through
the point (−1, 0).

show steps please
Find the equation of the line that is perpendicular to 2x + 5y = 8 and passes through
the point (−1, 0).

show steps please
@Mathematics

Answer 1

5y=-2x+8
y=-2/5x+8/5

slope=5/2

y=mx+b , m=5/2 , (-1,0)
0=5/2(-1)+b
0=-5/2+b
5/2=b

so the equation is, y=5/2x+5/2