Question

x^3a +1 of factoring binomial sum of cubes?

Answer 1

it is the sum of two cubes, assuming this is
\[x^{3a}+1\]

Answer 2

use
\[a^3+b^3=(a+b)(a^2-ab+b^2)\] with
\[a=x^a,b=1\]

Answer 3

is this good ?
\[(x ^{a}+1)(x ^{2a}-x ^{2}1+1^{2}) \]

Answer 4

close.
should be
\[(x^a+1)(x^{2a}-x^a+1)\]

Answer 5

thanks

Answer 6

yw