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4-500y^3 in factor complete?
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i think you have a difference of cubes there
yes i agree.:)
4(1-125^3)
i'm sure you know the rest
unh there the y in the equation.
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125y^3
still is a cube... 5y*5y*5y
onh
its not totally important but thats not an equation its an expression
the expansion would be 4(1-5y)(1+5y+25y^2)
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thank you
np
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