Question

need help on the attachment @Calculus1

Answer 1

that wasn't right

Answer 2

I got it wrong so its not option 5

Answer 3

it should be (mx^2/2)+b but that isn't a choice, but the closest to that is option 2.

Answer 4

it is option 2... once you evaluate it from 0 to 1 you are left with option 2.

Answer 5

yep correct, thanks so much

Answer 6

second one is right

Answer 7

correct

Answer 8

you're welcome

Answer 9

area of rectangle + area of triangle. rectangle has area b, triangle has area
\[\frac{1}{2}m\]