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What are the solutions for x in the proportion 2x+3 = 2x ---- ---- x 2 What are the solutions for x in the proportion 2x+3 = 2x ---- ---- x 2 @Mathematics
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4x+6=2x2 2x2-4x-6=0 x2-2x-3=0
x = 3 or, -1
(x-3)(x+1) x=3 x=-1
x^2 -3x+x-3=0 x(x-3) +1(x-3) = 0 (x-3)(x+1) = 0 therefore x = 3 or x = -1
explain the two ways to simplify \[\sqrt{320}\] and provide the simplified form.
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1.cross multiply 2.equation:2(2x+3)=2x^2 3.slove:4x+12=2x^2 4x+12-2x^2=0 (x-3)(x+1) x=3 & x=-1 :D
that's 320?
\[8\sqrt{5}\]
Yes
320 = 16 * 20 = 4^2 * 2^2 * 5 sqrt{320} = 8Sqrt{5}
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Explain
very simple. result: \[2x ^{2}-4x-6\] values: x=3 and x=-1
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