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Express the solution using natural logarithm. 3e^(1+x)=2.
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- so i think 3lne(1+x)=2lne 3(1+x)lne=2lne 3(1+x)=2 3+3x=2 3x=-1 x= -1/3
i think jonny the process may be like ts.. ln{e^(1+x)}=ln(2/3) 1+x=ln(2/3)
so x =ln(2/3)-1.. is it right jonny???
yes you think it right
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