Trigonometry find the distance between (4/5, -2/3) and (-8/5. -6). also the MIDPOINT and the SLOPE. Trigonometry find the distance between (4/5, -2/3) and (-8/5. -6). also the MIDPOINT and the SLOPE. @Mathematics
\[\underline{distance}=\sqrt{(y_2-y_1)^2 +(x_2 -x_1)^2}\]\[\underline{midpoint}= (\frac{x_1+x_2}{2} ,\frac{y_2+y_1}{2})\]\[\underline{slope} = \frac{y_2-y_1}{x_2-x_1}\]
can you help me in solving that?
try doing it, and i'll check ur answers for u if u want... i gave u the solution, u just need to plug in the pointts and ull get the answers
ok:))
in our book its x first b4 y..
in solving the distance
it doesnt matter,
d= \[\sqrt{7896/225}\]
??????
http://www.wolframalpha.com/input/?i=distance+between+%284%2F5%2C+-2%2F3%29+and+%28-8%2F5%2C-6%29.
is it right?
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