Question

When does the relative max occur
y= -x^3+ 3x^2-2
please help

Answer 1

Take the derivative and set it equal to 0
y'=-3x^2+6x=-3x(x-2)=0 x=2, x=0
Test the derivative for the intervals created by these values ( i use test points in the intervals)
y'(-1)<0
y'(1)>0
y'(3)<0 Since the derivative changes from positive to negative at x=2, a relative max occurs there

Answer 2

do u know the minimum

Answer 3

x=0 since derivative changes from negative to positive there