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two ships leave a port at 9AM. One travels at a bearing of N 53 degrees W at 12 miles per hour and the other travels at a bearing of S 67 degree W at 16 miles per our. Approximate how far apart they are at noon that day?
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d= 36^2 +48^2 - 2(36)(48)cos60 i dont have a calculator now :P
how did you get 36 , 48 and 60?
|dw:1321046461287:dw|
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