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Mathematics 21 Online
OpenStudy (anonymous):

Find the limit: limx^sinx as x approaches to 0+. Find the limit: limx^sinx as x approaches to 0+. @Mathematics

OpenStudy (anonymous):

1

OpenStudy (anonymous):

can you write down the process for solution?

OpenStudy (anonymous):

lim sinx = 0 x^0 = 1

OpenStudy (anonymous):

thanks.

OpenStudy (anonymous):

no problem

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