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solve w^4-18^2-2=0
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18w^2??
yes
let x=w^2 the eq becomes:x^2-18x-2=0 now solve this simple quadratic eq.
x^2-36w-2=0 am i right
the eq. becomes: (x-9)^2-81-2=0 (x-9)^2=83 (x-9)=+-sqrt(83) x=9+-sqrt(83) x=9-sqrt(83) is rejected w^2=9+sqrt(83) w=+-sqrt(9+sqrt(83))
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there willl be 4 answers
9-sqrt(83)<0....
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