Question

log(16x+2)+log(20x-2)=log(319x^2+9x-2) log(16x+2)+log(20x-2)=log(319x^2+9x-2) @Mathematics

Answer 1

This is supposed to be a puzzle for extra credit, but I already solved the puzzle, I just need to show work. So the answer is x=2.

Answer 2

solve
\[(16x+2)(20x+2)=319x^2+9x-2\] for x

Answer 3

good work satellite.........hey can i ask one thing from u @ satellite

Answer 4

That didnt work satellite :S

Answer 5

typo there, should be
\[(16x+2)(20x-2)=319x^2+9x-2\]
http://www.wolframalpha.com/input/?i=%2816x%2B2%29%2820x-2%29%3D319x%5E2%2B9x-2

Answer 6

you get two values for x, -1 and 2, but your only answer is 2 because if x = -1 then 20x -2 = -22 and you cannot take the log of a negative number

Answer 7

x^2 - x -2 = 0
solve for x

Answer 8

don't forget to drop the "-1" solution
@sheg, ask away