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solve using quadratic formula. x^2+(x+10)^2=50 solve using quadratic formula. x^2+(x+10)^2=50 @Mathematics
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\[x ^{2}+x ^{2}+20x+100-50=0\] \[2x ^{2}+20x+50=0\] a=2 b=20 c=50 \[\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\] \[\frac{-20 \pm \sqrt{20 ^{2}-4*2*50}}{2*2}\]
\[\frac{-20 \pm \sqrt{400-400}}{4}\]\[\frac{-20 }{4}\]=-5
x=-5
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