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in the figure angles α, β are positive. Find the value of α, β, and b.
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5^2=3^2+b^2-(2)(3)(b)cos32 find b from this equation b^2=5^2+3^2-(2)(5)(3)cosβ find β from this equation then α=180-32-β
b^2=34-6bcos32 where do i go from here?
from eq 1:b^2-6bcos32-16=0 this is a simple quadratic equation,u can get cos 32 with a calculator
I think it would be be a little simpler if you used the law of sines
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choose whichever method u like,after solving i got:b=7.29 alpha=19 betta=129,
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