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x^(log[3](x^2))+(log[3](x^2))^2-10=1/x^2
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\[x ^{\log 3(x ^{2})}+(\log 3(x^{2}))=1/x ^{2}\] Is that what you're looking for?
add the ^2-10 to log 3(x^2)
here 3 is base and remaning is N
-10 is seperate
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