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Draw each graph in the xy-plane. 2x-3y=-12
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Solve for y, then you can plug in some random x values to compute your y values to get a few points... since it will be a line, you only need two points...
y = 2x/3+4
the graph of 2x-3y=12 is
so it would be like this y|0|1|2|3| ------------------- x|-8|6|4|2| then graph?
If you plug 3 into (2x/3)+4 you get 6. If you plug in 6 you get 8.
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so two of your points would be (3,6) and (6,8)
oh damn I was doing a completely different problem! from this one my apologizes!
y(0)(2)(4) ---------------- x(6)(9)(12)
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