Question

\[\sqrt[9]{x}^{7} \over \sqrt[9]{x}^{7}\]

\[\sqrt[9]{x}^{7} \over \sqrt[9]{x}^{7}\]

@Mathematics

Answer 1

1

Answer 2

1

Answer 3

x^(7/9) /x^(7/9) = x^(7/9 - 7/9) = x^0 = 1

Answer 4

the second ^7 is suppose to be a ^5

Answer 5

^(7/9) /x^(5/9) =x^(7/9 - 5/9) = x^(2/9)

Answer 6

\[\sqrt[9]{x ^{2}}\]