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OpenStudy (anonymous):
Find the length of the side AB in the triangle ∆ABC in the figure
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OpenStudy (anonymous):
OpenStudy (mertsj):
sin122/10 = sinB/5 Angle B = 25 degrees so Angle C = 180-25-122=33 degrees. Now use the law of cosines: c^2 = a^2+b^2-2abcosC c^2=100+25-2(10)(5)cos33 c^2 = 125 -100(.8387) c^2 = 125 - 83.87 c^2=41.13 c=6.41
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