Question

Solve the equation without using logarithms.
3^9x=9^3x-6

Answer 1

3^9x = (3^2)^3x -6

Answer 2

3^9x = 3^6x-6
3^9x - 3^6x = -6

Answer 3

theres one answer
x=

Answer 4

is it 3^(9x)=9^(3x-6)

Answer 5

yes

Answer 6

-4?

Answer 7

o...

Answer 8

3^(9x) = 3^(6x-12)
9x = 6x -12
3x = -12
x = -4

Answer 9

\[3^{9x}=9^{3x-6}\]

Answer 10

-4 is correct

Answer 11

where did you get 6x-12 from?

Answer 12

\[9^{3x-6}=(3^{2})^{3x-6}=3^{6x-12}\]

Answer 13

how does (3^2)^3x-6 give you 3^6x-12?

Answer 14

multiply by 2 obviously but im a little confused

Answer 15

(a^m)^n=a^(m*n)

Answer 16

u just multiply the powers together?

Answer 17

yes

Answer 18

ok i see... THANKS a lot!