Question

I need help factoring the polynomial completely: 12(x-3)^2-2(x-3)-30

Answer 1

let y=x-3, so you then get 12y^2-2y-30=2(2y+3)(3y-5)
replace y to get expression in x.

Answer 2

let x-3 = u
12u^2 - 2u - 30
= 2(6u^2 - u - 15)
= 2(3u - 5 )(2u + 3 )

now replace u with x-3

2(3x- 9 - 5)(2x - 6 +3)
= 2(3x - 14)(2x - 3)

Answer 3

Thanks so much, that helped me a ton!

Answer 4

yw