Question

please help... The surface area of a right square pyramid whose base has sides of length 12 dm and whose slant height is 11 dm (on all four faces) is?

Answer 1

the base is a square so Area=side^2
144=12^2
The sides are 2 right angled triangles so Area=base*height
132=11*12
but there are four sides so
132*4=528
plus the base
528+144=672
Answer 672 dm^2

Answer 2

this really helped

Answer 3

glad it was helpful