Question

A long distance trucker traveled 260 miles in one direction during a storm. The return trip in rainy weather was accomplished at double the speed and took 5 hours less time. Find the speed going.

Answer 1

let x be speed going
then x = 260 / t..................(1)
speed returning = 2x
and time = t-5 hours

2x = 260 / t-5....................(2)
multiply (1) by 2:
2x = 520 /t
so
520/t = 260 / t-5
520t - 2600 = 260t
260t = 2600
t = 10

speed x = 260 / 10 = 26 mph

Answer 2

THX!!

Answer 3

no probs